Exercise 5.3.12

Answers

Considering the three states, new, once used, and twice used, the matrix is

A = (\begin{matrix} \frac{1}{3} & \frac{1}{3} & 1 \\ \frac{2}{3} & 0 & 0 \\ 0 & \frac{2}{3} & 0 \end{matrix}) .

It is regular. So we can just find the fixed vector

(\begin{matrix} \frac{9}{19} \\ \frac{6}{19} \\ \frac{4}{19} \end{matrix}) .

jephianlin

2011-06-27 00:00