Exercise 5.4.2

Answers

1.
Yes. For every ax2 + bx + c W, we have
T(ax2 + bx + c) = 2ax + b W.
2.
Yes. For every ax2 + bx + c W, we have
T(ax2 + bx + c) = 2ax2 + bx W.
3.
Yes. For every (t,t,t) W, we have
T(t,t,t) = (3t,3t,3t) W.
4.
Yes. For every at + b W, we have
T(at + b) = (a 2 + b)t W.
5.
No. For (10 0 2 ) W, we have
T(A) = (02 1 0 )W.
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2011-06-27 00:00
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