Exercise 5.4.40

Answers

Observe that

A - tI = (B_{1} - tI) \oplus (B_{2} - tI) \oplus \dots \oplus (B_{k} - tI) .

So we have

\det (A - tI) = \prod_{i = 1}^{k} \det (B_{i} - tI) .

jephianlin

2011-06-27 00:00