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Exercise 5.4.42

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Observe that the nullity of $A$ is $n - 1$ and $\det (A - nI) = 0$ because the sum of all column vectors of $A - nI$ is zero. So we know the characteristic polynomial of it is

{(- 1)}^{n} t^{n - 1} (t - n) .

jephianlin

2011-06-27 00:00

Exercise 5.4.42

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