Exercise 5.4.7

Answers

Let W be a T-invariant subspace and TW be the restricted operator on W. We have that

R(TW) = TW(W) = T(W) W.

So at least it’s a well-defined mapping. And we also have

TW(x) + TW(y) = T(x) + T(y) = T(x + y) = TW(x + y)

and

TW(cx) = T(cx) = cT(x) = cTW(x).

So the restriction of T on W is also a linear operator.

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2011-06-27 00:00
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