Exercise 6.1.28

Answers

Check the conditions one by one.

  • [x + z,y] = ℝe x + z,y = ℝe(x,y + z,y)
    = ℝe x,y + ℝe z,y = [x,y] + [z,y].
  • [cx,y] = ℝe cx,y
    = cℝe x,y = c[x,y],

    where c is a real number.

  • [x,y] = ℝe x,y = ℝe x,y¯
    = ℝe y,x = [y,x].
  • [x,x] = ℝe x,x = x,x > 0

    if x0.

Finally, we have [x,ix] = 0 since

x,ix = i x,x

is a pure imaginary number.

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2011-06-27 00:00
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