Exercise 6.1.7

Answers

1.

∥ cx ∥ = {⟨ cx, cx ⟩}^{\frac{1}{2}} = {(c \bar{c} ⟨ x, x ⟩)}^{\frac{1}{2}} = | c | ∥ x ∥ .

2.

This is the result of

∥ x ∥ = {⟨ x, x ⟩}^{\frac{1}{2}}

and Theorem 6.1(d).

jephianlin

2011-06-27 00:00