Homepage › Solution manuals › Stephen Friedberg › Linear Algebra › Exercise 6.11.13
Exercise 6.11.13
Answers
Use the notation in that Lemma. We know that
And compute that
for . Hence is -invariant.
2011-06-27 00:00
Homepage › Solution manuals › Stephen Friedberg › Linear Algebra › Exercise 6.11.13
Use the notation in that Lemma. We know that
And compute that
for . Hence is -invariant.