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Exercise 6.9.7

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Directly compute that ${(B_{v})}^{- 1} = B_{(- v)}$ . If $S^{'}$ moves at a negative velocity $v$ relative to $S$ . Then we have $S$ moves at a positive velocity $v$ relative to $S^{'}$ . Let $T_{v}$ be the transformation from $S$ to $S^{'}$ . Then we have ${[T_{v}^{- 1}]}_{β}] = B_{(- v)}$ and so ${[T_{v}]}_{β} = B_{v}$ .

jephianlin

2011-06-27 00:00

Exercise 6.9.7

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