Exercise 7.1.9

Answers

1.
The subspace W is T-invariant by Exercise 7.1.4. Let {vi}i be the cycle with initial vector v1. Then [TW]γ is a Jordan block by the fact
TW(v1) = λv1

and

TW(vi) = vi1 + λvi

for all i > 1. And β is a Jordan canonical basis since each cycle forms a block.

2.
If the ii-entry of [T]β is λ, then vi is an nonzero element in Kλ. Since Kλ Kμ = {0} for distinct eigenvalues λ and μ, we know that β is exactly those vi’s such that the ii-entry of [T]β is λ. Let m be the number of the eigenvalue λ in the diagonal of [T]β. Since a Jordan form is upper triangular. We know that m is the multiplicity of λ. By Theorem 7.4(c) we have
dim (Kλ) = m = |β|.

So β is a basis for Kλ.

User profile picture
2011-06-27 00:00
Comments