Exercise 7.2.16

Answers

Since the eigenvalue is zero now, observe that if x is an element in β corresponding to one dot called p, then T(x) would be the element corresponding to the dot just above the dot p. So the set described in the exercise is an independent set in R(Ti). By counting the dimension of R(Ti) by Theorem 7.9, we know the set is a basis for R(Ti).

User profile picture
2011-06-27 00:00
Comments