Exercise 7.4.7

Answers

By the definition of $m_{i}$ , we know the

N (ϕ_{i} {(T)}^{m_{i} - 1} \neq N (ϕ_{i} {(T)}^{m_{i}} = N (ϕ_{i} {(T)}^{m_{i} + 1} = K_{ϕ_{i}} .

Apply Theorem 7.24 and get the result.

jephianlin

2011-06-27 00:00