Exercise 1.1.19 (Caratheodory type property)

Let E d be a bounded set, and let F d be an elementary set. Show that

m,(J)(E) = m,(J)(E F) + m,(J)(EF)

Answers

We must demonstrate that

inf {m(B) : E B B is elementary } = inf {m(C) : E F C C is elementary }+inf {m(D) : EF D D is elementary }

We demonstrate that the left-hand side is both greater than or equal and less than or equal to the right-hand side.

  • Let C be an elementary outer cover of E F, and let D be an elementary outer cover of EF, and consider the quantity m(C) + m(D). Notice that E = (E F) (EF) C D; in other words, C D is an elementary cover of E. By finite subadditivity of elementary measure we have m(C D) m(C) + m(D), which proves the first part of the assertion.
  • Let B be an elementary outer cover of E. Then, E F B F, and EF BF. In other words, B F is an elementary outer cover of E F, and BF is an elementary outer cover of EF. Notice that we have by additivity property of elementary measure m(B) = m((B F) (BF)) = m(B F) + m(BF); thus, the left-hand side cannot exceed the right-hand side since we can always at least perform the above duplication.
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2020-03-30 00:00
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