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Exercise 1.1.9 (Compact convex polytopes are Jordan measurable)
Show that every compact convex polytope in is Jordan measurable.
Answers
First note the case is trivial since convex sets are intervals and compactness guarantees the polytope is a closed and bounded interval, which is an elementary box in . Thus, assume . Since the polytope is bounded, let be an elementary box containing the polytope. Furthermore, since the polytope is the intersection of finitely many half-spaces, let be one such half-space. It suffices to show the set is Jordan measurable, since intersecting these sets together for each will retrieve the polytope, and their intersection will be Jordan measurable by Exercise 1.1.6(1).
Let for some and , not all coordinates equal to . Without loss of generality, assume (the case is similar). Additionally, by Exercise 1.1.6(6) (translation invariance), we may assume has its first interval of the form for some . We identify with the subset of .
Now define the function by
where . Clearly, the graph of is the hyperplane boundary of . Now let and define the function by
Since constants and are continuous, we know is continuous. Define the set
where and . We claim that .
If , then and . Since , we know
which implies . Since , we know , which implies . Thus, , so .
Conversely, if , then and Since , we must have
Thus, and , the latter implying . Thus, . Since and , we know . Thus, , so .
Therefore, . Since is the region under the graph of the function minus the graph of the function, we know by Exercise 1.1.7 that is Jordan measurable.
Pedagogical notes: The intuition for the function can be attained from looking at the case and attempting to define in all cases the continuous function forming the top of the region . For the case, one should choose the first interval of to be of the form and let be the space between and the constant function .