Homepage › Solution manuals › Terence Tao › An Introduction to Measure Theory › Exercise 1.7.2 (Compatibility with Lebesgue measurability)

Exercise 1.7.2 (Compatibility with Lebesgue measurability)

Show that a set E ⊆ Rd is Carathéodory measurable with respect to Lebesgue outer measure if and only if it is Lebesgue measurable.

Answers

We verify both directions of the equivalence.

  • Suppose that E is Carathéodory measurable. In particular, μ∗(A) = μ∗(A ∩ E) + μ∗(A ∖ E) for any elementary set A ⊂ ℝd. Thus, by Exercise 1.2.17 (Carathéodory criterion, one direction), E is Lebesgue measurable.
  • Suppose that E is Lebesgue measurable. By Definition 1.2.2 (Lebesgue measurability), fix an arbitrary 𝜖 > 0 and let O𝜖 be an open set such that E ⊂ O𝜖 and m∗(O𝜖 − E) < 𝜖.
    Given any A ⊆Ω, we have, taking any any 𝜖 > 0

    μ∗(A) ≤ μ∗(A ∩ E) + μ∗(A ∩ Ec) ≤ μ∗(A ∩ O 𝜖) + μ∗((A ∩ O 𝜖c) ∪ (A ∩ O 𝜖 ∩ Ec)) ≤ μ∗(A ∩ O 𝜖) + μ∗(A ∩ O 𝜖c) + μ∗(A ∩ O 𝜖 ∩ Ec) ≤ μ∗(A ∩ O 𝜖) + μ∗(A ∩ O 𝜖c) + μ∗(O 𝜖 ∩ Ec) ≤ μ∗(A) + 𝜖

    where in the last step we used the fact that open sets are Carathéodory measurable. To sum up, we have proved that, for any 𝜖 > 0,

    μ∗(A) ≤ μ∗(A ∩ E) + μ(A ∩ Ec) ≤ μ ∗(A) + 𝜖.

    Taking limits as 𝜖 → 0, we obtain

    μ∗(A) = μ∗(A ∩ E) + μ(A ∩ Ec).

    Thus, E is Carathéodory measurable.

User profile picture
2021-09-06 00:00
Comments