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Exercise 0.23 (Simple consequences of the measure-theoretic axioms)

Let (Ω,Ω,μ) be a measure space.

1.
(Monotonicity) If E F are measurable, then μ(E) μ(F).
2.
(Subadditivity) If E1,E2, are measurable, then μ ( n=1En) n=1μ(En).
3.
(Continuity from below) If E1 E2 are measurable, then μ ( n=1En) = lim nμ(En).
4.
(Continuity from above) If E1 E2 are measurable and μ(E1) is finite, then μ ( n=1En) = lim nμ(En).

Answers

1.
(Monotonicity) By countable additivity property, we have μ(F) = μ (E [FE]) = μ(E) + μ(FE) μ(E).

2.
(Subadditivity) See Exercise 1.4.23 of An Introduction to Measure Theory.
3.
(Continuity from below) See Exercise 1.4.23 of An Introduction to Measure Theory.
4.
(Continuity from above) See Exercise 1.4.23 of An Introduction to Measure Theory.
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2021-08-01 00:00
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