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Exercise 1.41 ($L^p$-norm is non-decreasing in $p$)

Show that the expressions ∥X∥p are non-decreasing in p for p ∈ (0,+∞]. In particular, if ∥X∥p is finite for some p, then it is automatically finite for all smaller values of p.

Answers

Let p,q ∈ (0,+∞] such that p < q. The trick is to apply Jensen’s inequality. Recall that x↦xa is convex for any a > 0, in particular f(x) := xq p is convex. By Jensen’s inequality

f(E|X|p) = (E|X|p) q p ≤ Ef(|X|p) = E|X|q

from which we deduce

(E|X|p) q p ≤ E|X|q

so that

(E|X|p) 1 p ≤ (E|X|q) 1 q

as desired.

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2021-09-05 00:00
Comments
  • This is incomplete. $0 < a < b$ doesn't always imply that $a^{1/q} < b^{1/q}$ for $q > 0$, consider for example when $a, b \in (0, 1)$ and $q = 2$.
    isn • 2023-09-12