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Exercise 1.4 (Basic properties of the simple integral)

Let f,g : Ω → [0,∞] be simple unsigned functions.

1.
(Linearity) we have Simp∫ ℝdf + g = Simp∫ ℝdf + Simp∫ ℝdg
2.
(Equivalence) if almost everywhere f = g, then Simp∫ ℝdf = Simp∫ ℝdg.
3.
(Finiteness) we have Simp∫ ℝdf < ∞ if and only if (1) f is finite almost everywhere and (2) its support has finite measure.
4.
(Monotonicity) if almost everywhere f ≤ g then Simp∫ ℝdf ≤Simp∫ ℝdg.
5.
(Markov inequality) Show that for any 0 < t < ∞ we have μ ( {ω ∈Ω : f(ω) ≥ t}) ≤ 1 tSimp∫ Ωfdμ

Answers

We refer to the equivalent exercises from Terence Tao’s An Introduction to Measure Theory:

1.
See Exercise 1.4.33 (iii,iv).
2.
See Exercise 1.4.33 (vi).
3.
See Exercise 1.4.33 (vii).
4.
See Exercise 1.4.33 (i).
5.
Let f = c11E1 + … + cn1En be a simple representation of f and assume that c1 ≤… ≤ cn. Let 1 ≤ k ≤ n be such that c1,…,ck < t and ck+1,…,cn ≥ t. We then equivalently need to prove that ∑ i=k+1nμ(E i) ≤ 1 t∑ i=1nc iμ(Ei)

or, in other words,

∑ i=1nc iμ(Ei) −∑ i=k+1ntμ(E i) ≥∑ i=k+1n(c i − ti) ⋅ μ(Ei) ≥ 0.

But this follows by the definition of k.

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2021-08-09 00:00
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