Homepage Solution manuals Tom Leinster Galois Theory Exercise 4.1.7 (Generated Subfield Examples)

Exercise 4.1.7 (Generated Subfield Examples)

What is the subfield of generated by {78}? By {2 + 3i}? By {i}?

Answers

Solution: Since is of characteristic 0, by Lemma 2.3.16 the prime subfield of is . Since contains {78} and by definition of prime subfield, it is the intersection of all the subfields of containing {78}, hence is generated by {78}.

Let L be the subfield of generated by {2 + 3i}. Then L = {2a + 3bi : a,b } by similar argument as Example 4.1.6 (ii).

Similarly, let L be the subfield of generated by {i}. Then
L = {a + bi : a,b }=?{a + bi : a ,b }.

User profile picture
HN
2022-11-01 04:03
Comments
  • In (ii), $L = \mathbb{Q}[i]$, and in (iii), $L = \mathbb{C}$ (see the other solution).
    richardganaye2024-05-24

Proof. Here we write the set of subfields of .

If X , write

X = F , X F F

the subfield of generated by X .

(i)
We show that { 7 8 } = .

Here X = { 7 8 } . Since is the prime field of (because char = 0 : Lemma 2.3.16), = F F . But every subfield F contains , a fortiori contains X = { 7 8 } , so

X = F , X F F = F F = .

(ii)
We show that { 2 + 3 i } = ( i ) : = { a + bi a , b } .

Here X = { 2 + 3 i } . Note that, for every subfield F , if X F , then z = 2 + 3 i F , thus i = z 2 3 F . Since F , every a + bi with a , b is in F , which proves ( i ) F . Conversely, if ( i ) F , then F contains 2 + 3 i . This shows the following equivalences, for every subfield F of ,

X F 2 + 3 i F i F ( i ) F .

Therefore the smallest subfield of which contains 2 + 3 i is the smallest subfield of which contains ( i ) , that is ( i ) , since ( i ) is a subfield. More formally

{ 2 + 3 i } = X = F , X F F = F , ( i ) F F = ( i ) .

(iii)
We show that { i } = .

Here X = { i } . Every subfield F of which contains X , contains and i , so contains every z = a + bi with a , b . This proves F (so F = ). Therefore the smallest subfield of which contains X = { i } is . That is

{ i } = F , i F F = F , F F = F , = F F = .

User profile picture
2024-05-24 09:16
Comments