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Exercise 5.1.20 (Prime degree is simple)
Show that a field extension whose degree is a prime number must be simple.
Answers
Solution: Let be field extensions where and are arbitrary fields, , and , where is prime. By Theorem 5.1.17 (iii) we have . Hence, we must have that or , however, we also know that , hence , and therefore, , which by Example 5.1.3 tells us . Hence is a simple.
Comments
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Here we take $\alpha \in M, \alpha \not \in K$, so that $K(\alpha) \ne K$.richardganaye • 2024-05-25