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Exercise 5.1.20 (Prime degree is simple)

Show that a field extension whose degree is a prime number must be simple.

Answers

Solution: Let M : K(α) : K be field extensions where M and K are arbitrary fields, α M, and [M : K] = p, where p is prime. By Theorem 5.1.17 (iii) we have [M : K] = [M : K(α)][K(α) : K]. Hence, we must have that [K(α) : K] = 1 or p, however, we also know that K(α)K, hence [K(α) : K] = p, and therefore, [M : K(α)] = 1, which by Example 5.1.3 tells us M = K(α). Hence M : K is a simple.

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HN
2022-11-02 04:08
Comments
  • Here we take $\alpha \in M, \alpha \not \in K$, so that $K(\alpha) \ne K$.
    richardganaye2024-05-25