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Exercise 6.2.12 (Number of extensions)
Why does the proof of Proposition 6.2.11 not show that there are exactly isomorphisms extending ? How could you strengthen the hypotheses in order to obtain that conclusion? (The second question is a bit harder, and we’ll see the answer next week.)
Answers
Proof. The number of distinct roots of the irreducible polynomial (or ) may be less than if has multiple roots.
To strengthen the hypotheses, we can assume that every irreducible polynomial has only simple roots in (see the notion of separable extensions in §7.2). □