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Exercise 6.2.12 (Number of extensions)

Why does the proof of Proposition 6.2.11 not show that there are exactly [ M : K ] isomorphisms φ extending ψ ? How could you strengthen the hypotheses in order to obtain that conclusion? (The second question is a bit harder, and we’ll see the answer next week.)

Answers

Proof. The number s of distinct roots α j of the irreducible polynomial m (or ψ m ) may be less than deg ( m ) if m has multiple roots.

To strengthen the hypotheses, we can assume that every irreducible polynomial m K [ t ] has only simple roots in M (see the notion of separable extensions in §7.2). □

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2024-06-02 08:06
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