Exercise 1.17

In the setting of Section 1.46, prove that f D α f is a continuous mapping of C ( Ω ) into C ( Ω ) and also of K into K , for every multi-index α .

Answers

Proof. In both cases, D α is a linear mapping. It is then sufficient to establish continuousness at the origin. We begin with the C ( Ω ) case.

Let U be an aribtray neighborhood of the origin. There so exists N such that U contains

V N = { ϕ C ( Ω ) : max | D β ϕ ( x ) | β N , x K N < 1 N } . (1)

Now pick g in V N + α , so that

max D γ g ( x ) γ | N + | α , x K N < 1 N + α . (2)

(the fact that K N K N + α was tacitely used). The special case γ = β + α yields

max | D β D α g ( x ) | β N , x K N < 1 N . (3)

We have just proved that

g V N + α D α g V N , i.e. D α ( V N + α ) V N , (4)

which establishes the continuity of D α : C ( Ω ) C ( Ω ) .

To prove the continuousness of the restriction D α | K : K K , we first remark that the collection of the V N K is a local base of the subspace topology of K . V N + α K is then a neighborhood of 0 in this topology. Furthermore,

D α | K ( V N + α K ) = D α ( V N + α K ) (5) D α ( V N + α ) D α ( K ) (6) V N K ( see  ( 4 ) ) (7)

So ends the proof. □

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2020-01-24 00:00
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