Exercise 1.6

Prove that a set E in a topological vector space is bounded if and only if every countable subset of E is bounded.

Answers

Proof. It is clear that every subset of a bounded set is bounded. Conversely, assume that E is not bounded then pick V a neighbourhood of the origin: No counting number n = 1 , 2 , , verifies E nV (see Exercise 1 in Chapter 1). In other words, there exists a sequence { x 1 , , x n , } E such that

x n nV . (1)

As a consequence, x n n fails to converge to 0 as n tends to . In contrast, 1 n succeeds. It then follows from Section 1.30 that { x 1 , , x n , } is not bounded. So ends the proof. □

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2023-08-23 13:27
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