Exercise 1.12

Exercise 12: If z 1 , , z n , prove that

| z 1 + + z n | | z 1 | + + | z n |

Answers

Note that by the triangle inequality, | z 1 + z 2 | | z 1 | + | z 2 | . Assume the statement holds for n 1 . Then

| z 1 + + z n 1 + z n | | z 1 + + z n 1 | + | z n | | z 1 | + + | z n |

which establishes the claim by induction.

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2023-08-07 00:00
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Proof by induction. For n = 1 , there is nothing to show since | z 1 | = | z 1 | . For n = 2 , | z 1 + z 2 | | z 1 | + | z 2 | , which is true by Theorem 1.33 ( e ) . Suppose the inequality holds for n . Then,

| ( z 1 + + z n ) + z n + 1 | | z 1 + + z n | + | z n + 1 | | z 1 | + + | z n | + | z n + 1 | ,

where the last inequality holds by applying the inductive hypothesis to | z 2 + + z n | , and the inequality at each iteration holds by Theorem 1.33 ( e ) . □

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2023-09-01 19:13
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