Exercise 10.5

Exercise 5: Formulate and prove an analogue of Theorem 10.8, in which K is a compact subset of an arbitrary metric space.

Answers

We want to show: Suppose K is a compact subset of a metric space X , and { V α } is an open cover of K . Then there exists ψ 1 , , ψ s C ( X ) such that

  • 0 ψ i 1 for 1 i s ;
  • each ψ i has its support in some V α , and
  • ψ i ( x ) + + ψ s ( x ) = 1 for every x K .

Repeating the proof of Theorem 10.8 in the text and following the hint, associate with each x K an index α ( x ) so that x V α ( x ) . Then there are open balls B ( x ) and W ( x ) centered at x , with

B ( x ) ¯ W ( x ) W ( x ) ¯ V α ( x ) .

Since K is compact, there are points x 1 , , x s in K such that

K B ( x 1 ) B ( x s ) .

By Exercise 4.22, there are functions φ 1 , φ s C ( X ) such that φ i ( x ) = 1 on B ( x i ) ¯ , φ i ( x ) = 0 outside W ( x i ) , and 0 φ i ( x ) 1 on X , namely,

φ i ( x ) = ρ i 1 ( x ) ρ i 1 ( x ) + ρ i 2 ( x )

where ρ i 1 ( x ) is the distance from x to the complement of W ( x i ) , a closed set, and ρ i 2 ( x ) is the distance from x to B ( x i ) ¯ . Letting ψ 1 = φ 1 , and

ψ i + 1 = ( 1 φ 1 ) ( 1 φ i ) φ i + 1

for i = 1 , , s 1 , the remainder of the proof follows exactly as in the proof of Theorem 10.8.

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2023-08-07 00:00
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