Exercise 4.11

Exercise 11: Suppose f is a uniformly continuous mapping of a metric space X into a metric space Y and prove that { f ( x n ) } is a Cauchy sequence in Y for every Cauchy sequence { x n } in X . Use this result to give an alternative proof of the theorem stated in Exercise 13.

Answers

Let 𝜀 > 0 and let δ > 0 such that d Y ( f ( x ) , f ( y ) ) < 𝜀 if d X ( x , y ) < δ . Let { x n } be a Cauchy sequence in X . Then there is an integer N such that d X ( x n , x m ) < δ if n N and m N . Hence d Y ( f ( x n ) , f ( x m ) ) < 𝜀 if n N and m N , so { f ( x n ) } is a Cauchy sequence in Y .

Let E be a dense subset of a metric space X , and let f be a uniformly continuous mapping of X into a complete metric space Y . We can extend f to a function on all of X as follows. Let x X and { p n } be a sequence in E which converges to x . Then { f ( p n ) } is a Cauchy sequence in Y which converges to y Y since Y is complete. This sets up a well-defined function g from X to Y since if { p n } is another sequence in X converging to x , then { f ( p n ) } converges to y Y . Since f is uniformly continuous on D , for 𝜀 > 0 there is δ > 0 such that if p , p E with d X ( p , p ) < δ then d Y ( f ( p ) , f ( p ) ) < 𝜖 3 . There is an integer N such that d X ( p n , x ) < δ 2 and d X ( p n , x ) < δ 2 for all n N . Then for such n we have

d X ( p n , p n ) d X ( p n , x ) + d X ( x , p n ) < δ .

Also, there is an integer M N such that for all n > M we have d Y ( y , f ( p n ) ) < 𝜀 3 and d Y ( y , f ( p n ) ) < 𝜀 3 . Hence, for large enough n we have

d Y ( y , y ) d Y ( y , f ( p n ) ) + d Y ( f ( p n ) , f ( p n ) ) + d Y ( f ( p n ) , y ) < 𝜀 .

Considering the constant sequence { x } for x E , we see that g extends f to all of X . To see that g is uniformly continuous, let 𝜀 > 0 . Since f is uniformly continuous on E , there is δ > 0 such that if p , p E with d X ( p , p ) < δ then d Y ( f ( p ) , f ( p ) ) < 𝜖 3 . Let x , x X such that d X ( x , x ) < δ 3 , and let { p n } and { p n } be sequences in E which converge to x and x , respectively. Let n be a large enough integer so that d X ( p n , x ) < δ 3 and d X ( p n , x ) < δ 3 . Then

d X ( p n , p n ) d ( p n , x ) + d ( x , x ) + d ( x , p n ) < δ

so that d Y ( f ( p n ) , f ( p n ) ) < 𝜖 3 . Also, if n is large enough we have d Y ( g ( x ) , f ( p n ) ) < 𝜀 3 and d Y ( g ( x ) , f ( p n ) ) < 𝜀 3 . Hence, for large enough n we have

d Y ( g ( x ) , g ( x ) ) d Y ( g ( x ) , f ( p n ) ) + d Y ( f ( p n ) , f ( p n ) ) + d Y ( f ( p n ) , g ( x ) ) < 𝜀 .

Hence g is uniformly continuous on X .

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2023-08-07 00:00
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