Exercise 5.4

Exercise 4: If

C 0 + C 1 2 + + C n 1 n + C n n + 1 = 0 ,

where C 0 , , C n are real constants, prove that the equation

C 0 + C 1 x + + C n 1 x n 1 + C n x n = 0

has at least one real root between 0 and 1.

Answers

(Matt “Frito” Lundy)
Let:

f ( x ) = i = 0 n C i x i + 1 i + 1 .

Then we are looking for an x ( 0 , 1 ) such that f ( x ) = 0 . But f ( x ) is continuous in [ 0 , 1 ] , differentiable in ( 0 , 1 ) , f ( 0 ) = 0 , and f ( 1 ) = 0 . So by “the” mean value theorem, there exists an x ( 0 , 1 ) such that f ( x ) = 0 , as desired.

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2023-08-07 00:00
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