Exercise 7.10

Exercise 10: Letting ( x ) denote the fractional part of the real number x , consider the function

f ( x ) = n = 1 ( nx ) n 2 ( x real ) .

Find all discontinuities of f , and show that they form a countable dense set. Show that f is nevertheless Riemann-integrable on every bounded interval.

Answers

The discontinuities of the n th term, f n ( x ) = ( nx ) n 2 , occur at the rational numbers m n for any integer m . Let y = p q be a rational number where p and q have no common divisors. Then f n is discontinuous at y if and only if n is a multiple of q . Let g q = m ( mqx ) ( mq ) 2 , which is discontinuous at y , and let h q = f g q . Then the partial sums of h q are all continuous at y , hence by Theorem 7.11, h q is also continuous at y , and so f = g q + h q is discontinuous at y . If the real number z is irrational, then the partial sums of f are all continuous at z , hence by again applying Theorem 7.11 we have f is continuous at z . Therefore the discontinuities of f are the rational numbers, a countable dense subset of the real numbers.

The partial sums of f converge uniformly to f and are all Riemann-integrable on bounded intervals. Hence by Theorem 7.16, f is also Riemann-integrable on bounded intervals.

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2023-08-07 00:00
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