Exercise 7.20

Exercise 20: If f is continuous on [ 0 , 1 ] and if

0 1 f ( x ) x n dx = 0 ( n = 0 , 1 , 2 , ) ,

prove that f ( x ) = 0 on [ 0 , 1 ] .

Answers

Following the hint, note that by the linearity of Riemann-integration, 0 1 f ( x ) P ( x ) dx = 0 for all polynomials P . By Theorem 7.26 there exists a sequence of polynomials P n which converge to f uniformly on [ 0 , 1 ] . Since [ 0 , 1 ] is compact, f and each P n are bounded on [ 0 , 1 ] , so f ( x ) P n ( x ) converges uniformly to f 2 ( x ) by Exercise 7.2. By Theorem 7.16, 0 = 0 1 f ( x ) P n ( x ) dx must converge to 0 1 f 2 ( x ) dx , so this integral equals 0. Hence f ( x ) = 0 on [ 0 , 1 ] by Exercise 6.2.

User profile picture
2023-08-07 00:00
Comments