Exercise 8.17

Exercise 17: Assume f is bounded and monotonic on [ π , π ) , with Fourier coefficients c n as given by (62).

(a) Use Exercise 17 of Chapter 6 to prove that { n c n } is a bounded sequence.

(b) Combine (a) with Exercise 16 and with Exercise 14(e) of Chapter 3, to conclude that

lim N s N ( f ; x ) = f ( x + ) + f ( x ) 2

for every x .

(c) Assume only that f R on [ π , π ] and that f is monotonic in some segment ( α , β ) [ π , π ] . Prove that the conclusion of (b) holds for every x ( α , β ) .

Answers

(a) Using Exercise 6.17, with G ( x ) = ( i n ) e inx ,

n c n = n 2 π π π f ( x ) e inx dx = i 2 π ( f ( π ) e inπ f ( π ) e inπ ) i 2 π π π e inx df | n c n | 1 2 π ( f ( π ) f ( π ) ) + 1 2 π π π 1 df = 1 π ( f ( π ) f ( π ) )

(b) Since | n c n | M = ( f ( π ) f ( π ) ) π , we can apply Exercise 3.14(e) to get

lim N s N ( f ; x ) = lim N σ N ( f ; x ) = f ( x + ) + f ( x ) 2 .

The last equality is from Exercise 16.

(c) Letting

f ~ ( x ) = { f ( α ) π x α f ( x ) α x β f ( β ) β x π

then f ~ is monotonically increasing on [ π , π ] , so by part (b) we have

lim N s N ( f ~ ; x ) = f ~ ( x + ) + f ~ ( x ) 2

for all π x π . Hence by the localization theorem, since f ( x ) = f ~ ( x ) for α < x < β , we have

lim N s N ( f ; x ) = lim N s N ( f ~ ; x ) = f ~ ( x + ) + f ~ ( x ) 2 = f ( x + ) + f ( x ) 2

for α < x < β .

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2023-08-07 00:00
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