Exercise 9.20

Exercise 20: Take n = m = 1 in the implicit function theorem, and interpret the theorem (as well as its proof) graphically.

Answers

If the real-valued function f ( x , y ) is smooth and nonconstant in a region of 2 , then the solution of f ( x , y ) = 0 is locally a smooth curve. If D 1 f ( x 0 , y 0 ) 0 at a point of the curve, then the curve doesn’t have a vertical tangent at ( x 0 , y 0 ) , and so it will be the graph of a function y = g ( x ) near x = x 0 , so that f ( x , g ( x ) ) = 0 . Similarly, if D 2 f ( x 0 , y 0 ) 0 , then the curve doesn’t have a horizontal tangent at ( x 0 , y 0 ) , and so it will be the graph of a function x = h ( y ) near y = y 0 , so that f ( h ( y ) , y ) = 0 .

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2023-08-07 00:00
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