Exercise 9.29

Exercise 29: Let E be an open set in n . The classes C ( E ) and C ( E ) are defined in the text. By induction C ( k ) ( E ) can be defined as follows, for all positive integers k : To say that f C ( k ) ( E ) means that the partial derivatives D 1 f , , D n f belong to C ( k 1 ) ( E ) .

Assume f C ( k ) ( E ) , and show (by repeated application of Theorem 9.41) that the k th-order derivative

D i 1 i 2 i k f = D i 1 D i 2 D i k f

is unchanged if the subscripts i 1 , , i k are permuted. For instance, if n 3 , then D 1213 f = D 3112 f for every f C ( 4 ) .

Answers

If we let g = D i n + 1 i k f , then by Theorem 9.41 we have

D i 1 i k f = D i 1 i n 2 ( D i n 1 i n g ) = D i 1 i n 2 ( D i n i n 1 g ) = D i 1 i n 2 i n i n 1 i k f ,

that is, we can swap any two adjacent indices and the derivative remains unchanged. We can apply this result to show that we can swap any two indices:

D i 1 i m i n i k f = D i 1 i m i n i n 1 i n + 1 i k f = (keep swapping adjacent indices until i n comes before i m ) = D i 1 i n i m i n 1 i n + 1 i k f = D i 1 i n i m + 1 i m i n 1 i n + 1 i k f = (keep swapping adjacent indices until i m comes after i n 1 ) = D i 1 i m 1 i n i m + 1 i n 1 i m i n + 1 i k f

Since any permutation is the result of pairwise swaps (this is usually shown in elementary abstract algebra courses when discussing the permutation group), we see that in the case of f C ( k ) , we can permute the order of partial differentiation without changing the derivative.

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2023-08-07 00:00
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