Exercise 1.12

Suppose f L 1 ( μ ) . Prove that to each 𝜖 > 0 there exists a δ > 0 such that E | f | < 𝜖 whenever μ ( E ) < δ .

Answers

Proof. Let E N : = { x X | f ( x ) | N } . Then, letting f N : = | f | χ E N , we have | f N | f N + 1 , and the f N | f | , so by the monotone convergence theorem, for every 𝜖 > 0 there exists an N such that

X ( | f | f n ) < 𝜖 2

for all n N . Now let δ such that < 𝜖 2 . Then,

E | f | E ( | f | f n ) + E f n X ( | f | f n ) + < 𝜖 .
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2021-12-22 00:00
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