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Yaser Abu-Mostafa
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Learning from Data
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Exercise 2.7
Learning from Data
Exercise 2.7
Answers
(a)
P
[
h
(
x
)
≠
f
(
x
)
]
=
P
[
h
(
x
)
≠
f
(
x
)
]
⋅
1
+
P
[
h
(
x
)
=
f
(
x
)
]
⋅
0
=
P
[
h
(
x
)
≠
f
(
x
)
]
(
h
(
x
)
−
f
(
x
)
)
2
+
P
[
h
(
x
)
=
f
(
x
)
]
(
h
(
x
)
−
f
(
x
)
)
2
=
E
[
(
h
(
x
)
−
f
(
x
)
)
2
]
(b)
P
[
h
(
x
)
≠
f
(
x
)
]
=
1
4
P
[
h
(
x
)
≠
f
(
x
)
]
⋅
4
+
1
4
P
[
h
(
x
)
=
f
(
x
)
]
⋅
0
=
1
4
P
[
h
(
x
)
≠
f
(
x
)
]
(
h
(
x
)
−
f
(
x
)
)
2
+
1
4
P
[
h
(
x
)
=
f
(
x
)
]
(
h
(
x
)
−
f
(
x
)
)
2
=
1
4
E
[
(
h
(
x
)
−
f
(
x
)
)
2
]
niuers
2021-12-07 22:09
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