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Learning from Data

Exercise 4.5 (Tikhonov regularizer)

Answers

(a): $\sum_{q = 0}^{Q} w_{q}^{2} = [w_{1}, w_{2}, \dots, w_{Q}] [\begin{matrix} w_{1} \\ w_{2} \\ \dots \\ w_{Q} \end{matrix}] = w^{T} w$ , so $Γ = I$ .
(b): ${(\sum_{q = 0}^{Q} w_{q})}^{2} = [w_{1}, w_{2}, \dots, w_{Q}] [\begin{matrix} 1 \\ 1 \\ \dots \\ 1 \end{matrix}] [1, 1, \dots, 1] [\begin{matrix} w_{1} \\ w_{2} \\ \dots \\ w_{Q} \end{matrix}]$ , so $Γ = [1, 1, \dots, 1]$ .

niuers

2021-12-08 09:28

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