Exercise 3.3.6

Prove that if A and B are similar, then det A = det B.

Answers

Proof. A and B are similar, then A = Q1BQ for an invertible matrix Q. Then

det A = det Q1BQ = (det Q1)(det B)(det Q) = (det Q1)(det Q)(det B) = (det Q1Q)(det B) = (det I)(det B) = det B.
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2018-11-29 00:00
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